A force F acting on an object varies with distance x as shown in fig. The work done by the force in moving the object from x = 0 to x = 6 m is:
Correct answer: B. 13.5 J
- A. 18 J
- B. 13.5 J
- C. 9 J
- D. 4.5 J
Explanation
W = Area under F - x graph W= 1/2 (Sum of parallel sides) (Perpendicular distance between parallel sides) = 1/2(6+3)(3) =13.5 J
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About Work and Energy
Work transfers energy when a force causes displacement, while kinetic energy, gravitational potential energy and power describe motion, position and the rate of energy transfer. The work-energy theorem links net work with change in kinetic energy, and efficiency accounts for energy losses rather than treating them as energy destruction.
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