A fair coin is tossed four times. What is the probability of getting exactly two heads?
Correct answer: C. 3/8
- A. 1/8
- B. 1/4
- C. 3/8
- D. 1/2
Explanation
This follows a binomial distribution with n = 4, p = 1/2, and r = 2. The probability is C(4,2)(1/2)^2(1/2)^2 = 6/16 = 3/8.
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