A cylindrical resonance tube, opened at both ends, has a fundamental frequency 'f' in the air asshown in figure I. As shown in figure II, if half of the length of the resonance tube is dipped vertically into water,then the fundamental frequency in the air will be
Correct answer: A. f / 2
- A. f / 2
- B. f
- C. 2f
- D. 4f
Explanation
The fundamental frequency of a cylindrical resonance tube opened at both ends is determined by the length of the air column. When half of the tube is submerged in water, the effective length of the air column is halved. This results in the fundamental frequency being halved as well, making it f / 2. Option A is correct. Option B is incorrect because the frequency would remain unchanged only if the air column's length remained unchanged. Option C and Option D are incorrect because they imply an increase in frequency, which would require a reduction in the length of the air column beyond the effect of submerging half the tube.
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About Organ Pipes
Organ pipes produce standing sound waves in air columns, with resonance determined by whether each end is open or closed. The topic covers nodes, antinodes, fundamental frequency, harmonics, wavelength and end correction. Open pipes support all harmonics, while closed pipes support only odd harmonics under the ideal model.
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