A cycle wheel of radius 0.4 m completes one revolution in one second, then the acceleration of a point on the cycle wheel will be
Correct answer: B. 1.6π2m/s2
- A. 0.8m/s2
- B. 1.6π2m/s2
- C. 0.4m/s2
- D. 0.4π2m/s2
Explanation
Option B is correct. EXPLANATION: To find the acceleration of a point on the cycle wheel, you need to calculate the angular velocity and use the formula for angular acceleration. In this case, the correct formula is a = rω2. Option B correctly calculates the acceleration using the given data and formula, resulting in an acceleration of approximately 1.6π2 m/s2. The other options provide incorrect calculations or use the wrong formulas, leading to inaccurate results.Using, ω = 2πn = 2π × 1 = 2π rad/s a = rω² = 0.4 × (2π)² a = 1.6 π² m/s²= 0.4 × 4 π²=1.6π2m/s2
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Rotational motion relates angular displacement, angular velocity and angular acceleration to linear displacement, tangential velocity and tangential acceleration through the radius. Questions use radians, v equals r omega and tangential acceleration, while distinguishing tangential velocity from centripetal acceleration and angular quantities from their linear counterparts.
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