A current of 5 Amperes flows in a resistor of 2 Ohms. Calculate the energy dissipated in 300 seconds in the resistor:
Correct answer: C. 15 KJ
- A. 5 KJ
- B. l0 KJ
- C. 15 KJ
- D. 20 KJ
Explanation
I=5AR=2 ohmst=300 sE=?As, power P=I2RP=522P=252P= 50 WAlso, P=Energy/timeenergy = power X timeenergy = 50300energy =15,000J energy = 15kJ
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