A cubic vessel of height 1 m is full of water, the minimum work done in taking water out:

Explanation

To determine the minimum work done in taking water out of the cubic vessel, we need to calculate the loss of gravitational potential energy. The gravitational potential energy can be calculated using the formula: PE = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height. In this case, the height is given as 1 m. However, since the vessel is filled with water, we need to consider the height from the center of the vessel to the surface of the water, which is 0.5 m. Assuming the density of water to be 1000 kg/m³ and the volume of the cubic vessel to be 1 m³, we can calculate the mass of water as follows: mass = density × volume = 1000 kg/m³ × 1 m³ = 1000 kg Now we can calculate the gravitational potential energy: PE = mgh = 1000 kg × 10 m/s² × 0.5 m = 5000 J Therefore, the minimum work done in taking water out of the cubic vessel is 5000 J.