A cooler of 1500 W, 200 volt and a fan of 500 W, 200 volts are to be used from a household supply. The rating of fuse to be used is:
Correct answer: D. 10 A
- A. 2.5 A
- B. 5.0 A
- C. 7.5 A
- D. 10 A
Explanation
The total power drawn by the appliances is Ptotal = 1500 W + 500 W = 2000 W. The total current drawn from the 200 V supply is I = Ptotal / V = 2000 W / 200 V = 10 A. A 10A fuse is required.
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