Asked in PMC Practice Test 33 (2021) 2021Moderate

A constant force of 10N is applied in horizontal direction and distance travelled in the direction of force is 2m,then work done is _.

Correct answer: B. 20J

  • A. 50J
  • B. 20J
  • C. 22J
  • D. 10J

Explanation

The work done is calculated using the formula: Work = Force x Distance x Cosine(angle)As the force is applied in the horizontal direction, the angle between the force and the displacement is 0 degrees, and cosine(0) = 1. Therefore, we can simplify the formula to:Work = Force x DistanceSubstituting the given values, we get:Work = 10 N x 2 m = 20 Joules (J)Therefore, the work done is 20 J. Mathematically the other options are incorrect

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About Work

Work is done when a force produces displacement, with its value determined by the component of force along the displacement. The topic covers positive, negative and zero work, work by variable forces from force-displacement graphs, and the connection between net work and change in kinetic energy.

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