A constant force F= 2i + 3j +4k is applied on a body. What will be the work done to move the body 5m in the z-direction?
Correct answer: D. 20 J
- A. 0
- B. 10 J
- C. 45 J
- D. 20 J
Explanation
We know that work done = F x dwhere F is the force and d is the displacement in the direction of the force.The question statement says a constant force, F = 2i + 3j + 4k is applied. The component of force in the z-direction (direction of displacement of the body) = 4NTherefore, Work done = 4 x 5This equals to 20 J.
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