A conductor of length 1m, carrying a current of 1A is placed at an angle of 45o to the magnetic field of 1 gauss. The force acting on the conductor is
Correct answer: B. 1/√2 x 10^-4 N
- A. Zero
- B. 1/√2 x 10^-4 N
- C. 1/√2 N
- D. 5 x 10^-4 N
Explanation
To find the force acting on a conductor in a magnetic field, we use the formula: F = BIL sin(θ). Here, B (magnetic field strength) is 1 gauss, which converts to 1 x 10-4 T (Tesla). The length L is 1m, the current I is 1A, and the angle θ is 45°.Plugging these values into the formula:F = (1 x 10-4 T)(1 A)(1 m)sin(45°) = (1 x 10-4)(1)(1)(1/√2) = 1/√2 x 10-4 N.Thus, the correct answer is 1/√2 x10-4 N. All other options either imply a zero force or overestimate the force based on the provided conditions, making them incorrect.
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Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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