A compound of sodium oxide has 74.2% of sodium and 25.8% of Oxygen. The empirical formula of the compound is?
Correct answer: C. Na2O
- A. Nao
- B. NaO2
- C. Na2O
- D. Na2O2
Explanation
Let's find the empirical formula step-by-step 👇1️⃣ Assume 100 g of the compound → Na = 74.2 g, O = 25.8 g2️⃣ Convert to moles: Na = 74.2 ÷ 23 = 3.23 mol O = 25.8 ÷ 16 = 1.61 mol3️⃣ Find the simplest ratio: Na : O = 3.23 ÷ 1.61 : 1.61 ÷ 1.61 = 2 : 1✅ Empirical formula = Na₂O
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