A compound has an empirical (simple) formula, C2H2O. If the experimental molecular weight is found to be in the range 160-170, the molecular formula of this compound is: (Atomic weight: C = 12.1, H = 1.008, O = 16).
Correct answer: C. C8H8O4
- A. C3H6O3
- B. C4H4O2
- C. C8H8O4
- D. C6H6O3
Explanation
The empirical mass formula is 42, i.e., [2(12) + 2(1) + 16]. Multiplying the empirical formula mass by 4 will result in a molecular mass of 168, which is between 160 and 170, and would give us the molecular mass of C8H8O4.
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