A circular loop of area 200 cm2 sits in a x-z plane. Then a uniform magnetic field, B = (0.3i + 0.4j) T is applied on it, find the magnetic flux through the loop:
Correct answer: C. 0.008 wb
- A. 0.8 wb
- B. 8 wb
- C. 0.008 wb
- D. 0.08 wb
Explanation
B, that stands for the magnetic field strength= (0.3i + 0.4j) T.A vector, that stands for the area vector, comprises of the Area, in meters, and the direction;Area, in meters= 200 cm2 --> 0.02 m2The circle lies is in the x-z plane so, perpendicular to it is the x-y plane. Therefore, the area vector would be in the x-y plane thus, 'j'.Magnetic Flux = B vector x Area vector *Only the B vector, that is in the direction of the Area vector would be considered.= 0.4j x 0.02j = 0.008 Wb.
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About Electromagnetism
Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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