A charge of 2C experiences a force 2000N in a uniform electric field. In this field the potential differences between two points seperated by a distance 1cm is:
Correct answer: C. 10V
- A. 2V
- B. 5V
- C. 10V
- D. 20V
Explanation
The correct option is CGiven q=2C , F=2000N , d=10-2 Electric field = E = F/q = 2000/10-2=1000The potential difference V =E.d=1000 X 10-2 =10V
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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