A certain volume of a gas at zero degree Celsius temperature and 1 atm pressure is 0.5 L. If the temperature is raised to 300 degrees Celsius by keeping the pressure constant, then what will be its final volume?
Correct answer: C. 1.05 L
- A. 1L
- B. 0.1L
- C. 1.05 L
- D. 1.50L
Explanation
This is the correct solution given below: P1 = 1 atm V1 = 0.5 L ( 0.5 dm3 ) T1 = 0o C ( 0 + 273 = 273 K) P2 = 1 atm T2 = 300o C ( 300 + 273 = 573 K) V2 = ? Use the eqn: P1V1 / T1 = P2V2 / T2 1 x 0.5 / 273 = 1 x V2 / 573 => V2 = 1.05 L
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About Charles's Law
At constant pressure, the volume of a fixed mass of gas is directly proportional to its absolute temperature. Questions involve the Kelvin scale, the equation V₁/T₁ = V₂/T₂, volume-temperature graphs, and the need to distinguish Charles's law from Boyle's law, which relates pressure and volume.
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