A catalyst is more effective when it is in the finely divided state because:
Correct answer: B. This increases the surface area of the catalyst
- A. The valence electrons are easily available
- B. This increases the surface area of the catalyst
- C. It attains equilibrium quickly
- D. All of the above
Explanation
Option b is correct. A catalyst is more effective when it is in the finely divided state because it increases the surface area of the catalyst. This allows more reactant molecules to come into contact with the catalyst, increasing the likelihood of successful collisions and hence speeding up the reaction.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Chemical Equilibrium
Reversible reactions reach dynamic equilibrium when forward and reverse rates become equal, and Le Chatelier's principle predicts the effect of changing concentration, pressure or temperature. The chapter also covers solubility product, the common ion effect, buffer action and the conditions used in Haber's process, with equilibrium shifts distinguished from changes in the equilibrium constant.
Practise Chemical Equilibrium
625 free Chemical Equilibrium MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Chemical Equilibrium questions
Which of the following is correct?
For a certain chemical reaction, the slope of the plot was determined and plotted against the concentration (a-x)2 and a straight line was obtained. It indicates that the reaction is of:
Consider the following general reaction: IA+IB → products. Rate of this reaction is expressed as: Rate = K[A]1[B]1 The correct order of reaction and molecularity is:
Change in concentration of a reactant is plotted against time and the slope dx/dt determined. The values of dx/dt are plotted against (a-x)2 and a straight line is obtained. It may be concluded that the reaction is:
Choose the one which is not an assumption of collision theory of reaction rate:
In which of the following reactions decrease or increase in pressure have no effect on the change of direction of the reaction?