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A car battery has EMF of 12 volts and internal resistance 5 x 10^-2 ohm. If it draws 60 ampere current, then terminal voltage of the battery will be:

Correct answer: D. 9 volts

  • A. 5 volts
  • B. 3 volts
  • C. 15 volts
  • D. 9 volts

Explanation

E= V+IrV = E-Ir = 12-(60)(5×10-2) = 9 volts

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About Current Electricity

Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.

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