A car at rest starts moving with linear uniformly increasing velocity. After 20 seconds, it attains the maximum velocity of 80 m/s. What is the distance covered during this time interval?
Correct answer: C. 800 m
- A. 200 m
- B. 400 m
- C. 800 m
- D. 1600 m
Explanation
The acceleration of the car is constant as it undergoes uniformly increasing velocity. Let the initial velocity of the car be u = 0 m/s, and final velocity be v = 80 m/s. The time taken to achieve this velocity is t = 20 s.Using the formula for uniformly accelerated motion, we have:v = u + atwhere a is the acceleration. Rearranging the equation, we get:a = (v - u)/t = 80 m/s / 20 s = 4 m/s2To find the distance covered by the car during the given time interval, we use the formula:s = ut + (1/2)at2where s is the distance traveled. Substituting the given values, we get:s = (1/2)(4 m/s2)(20 s)2 = 800 mTherefore, the correct answer is C) 800 m.
This question appeared on the NUMS 2019 (cancelled sitting) paper, which you can sit online with every answer explained.
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About Acceleration
Acceleration measures the rate at which velocity changes with time, including changes in speed, direction or both. Work includes average and instantaneous acceleration, the relation a = Δv/Δt, uniform acceleration equations, and interpreting velocity time and displacement time graphs, with acceleration carefully distinguished from velocity.
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