A body starts sliding on a rough horizontal surface with a speed of 10 m/s. If the coefficient of friction is 0.2, find the distance traveled by the body before coming to rest. (g = 10m/s)
Correct answer: B. 25 m
- A. 15 m
- B. 25 m
- C. 35 m
- D. 40 m
- E. 55 m
Explanation
Given that: v = 10 and u = 0.2 and g = 10 Solution = Using F = μN then, = μmg (here N = mg) So from above (ma = μmg); we got a = μg Now a = 0.2×10 = 2 m/s2Now using equation of motion V2=u2+2as 0 = 10×10 +2×2×s In solving it, we got s = 100/4 = 25 m Hence we get the correct answer.
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