A body of mass 100 g is revolving in a horizontal circle. If its frequency of rotation is 3.5 rps and radius of circular path is 0.5 m, the angular speed of the body is:
Correct answer: C. 22 rad/s
- A. 18 rad/s
- B. 20 rad/s
- C. 22 rad/s
- D. 24 rad/s
Explanation
The explanation is: To find the angular speed of the body, we need to relate it to the frequency of rotation.The relationship between angular speed (ω), frequency (f), and 2π (a full revolution in radians) is given by: ω = 2πf In this case, the frequency of rotation is given as 3.5 rps (revolutions per second). ω = 2π * 3.5 radians/second The angular speed is equal to 2π times the frequency. Now, we can calculate the angular speed: ω = 2π * 3.5 radians/second= 7π radians/second = 22 rad/s Therefore, the angular speed of the body is 22 radians/second.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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