A body is thrown with the velocity (4i+3j)m/s. Its maxium height is (g=10m/s2)
Correct answer: D. 0.45m
- A. 2.5m
- B. 0.8m
- C. 0.9m
- D. 0.45m
Explanation
The correct answer is 0.45 m. The maximum height in projectile motion is determined by the vertical component of the initial velocity (3 m/s) and the acceleration due to gravity (10 m/s²). Using the formula h = (u^2) / (2g), we calculate h = (3^2) / (2 * 10) = 0.45 m.Options A, B, and C are incorrect because they result from errors in applying the formula or misinterpretations of the given initial conditions.
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About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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