Asked in UHS MDCAT 2015 2015Moderate

A body is having weight 20 N, when the elevator is descended with a = 0.1 ms-2, then the value of tension 'T' is:

Correct answer: B. 19.8 N

  • A. 196 N
  • B. 19.8 N
  • C. 1.98 N
  • D. 2 N

Explanation

19.8 N: This option is the correct value for the tension 'T' when the elevator is descended with an acceleration of 0.1 m/s². The tension in the cable can be calculated using the equation T = mg - ma, where 'm' is the mass of the body, 'g' is the acceleration due to gravity, and 'a' is the acceleration of the elevator. Substituting the given values, T = (20 N) - (0.1 m/s²) = 19.8 N.

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