A body is having weight 20 N, when the elevator is descended with a = 0.1 ms-2, then the value of tension 'T' is:
Correct answer: B. 19.8 N
- A. 196 N
- B. 19.8 N
- C. 1.98 N
- D. 2 N
Explanation
19.8 N: This option is the correct value for the tension 'T' when the elevator is descended with an acceleration of 0.1 m/s². The tension in the cable can be calculated using the equation T = mg - ma, where 'm' is the mass of the body, 'g' is the acceleration due to gravity, and 'a' is the acceleration of the elevator. Substituting the given values, T = (20 N) - (0.1 m/s²) = 19.8 N.
This question appeared on the UHS MDCAT 2015 paper, which you can sit online with every answer explained.
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