A body is falling freely under gravity. How much distance it falls during an interval of time between 1st and 2nd seconds of its motion? (taking g = 10ms-2)
Correct answer: A. 15 m
- A. 15 m
- B. 5 m
- C. 20 m
- D. 25 m
Explanation
To calculate the distance fallen during the interval between the 1st and 2nd seconds, we use the kinematic equation for uniformly accelerated motion: d = 1/2 * g * t^2.First, find the distance fallen at the end of 2 seconds: d_2 = 1/2 * 10 * (2)^2 = 20 m.Then, find the distance fallen at the end of 1 second: d_1 = 1/2 * 10 * (1)^2 = 5 m.The distance fallen between the 1st and 2nd second is the difference: d = d_2 - d_1 = 20 m - 5 m = 15 m.Option A is correct. Option B represents the distance fallen in the first second only, Option C is the total distance after 2 seconds, and Option D is unrelated to the correct calculations.
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