A block of mass 60 kg just slides over a horizontal distance of 0.9 m. If the coefficient of friction between their surfaces is 0.15, then work done against friction will be:
Correct answer: A. 79.4J
- A. 79.4J
- B. 97.54J
- C. 105.25J
- D. 81J
Explanation
Work done = 0.15*(60*9.8)*0.9 J = 79.4 J
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About Work
Work is done when a force produces displacement, with its value determined by the component of force along the displacement. The topic covers positive, negative and zero work, work by variable forces from force-displacement graphs, and the connection between net work and change in kinetic energy.
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