A battery of emf 24 V and internal resistance 1 Ω is connected to two resistors of 3 Ω and 6 Ω in series. The current in the circuit is:
Correct answer: A. 2 A
- A. 2 A
- B. 3 A
- C. 4 A
- D. 6 A
Explanation
Total resistance = R₁ + R₂ + r = 3 + 6 + 1 = 10 Ω. Current I = E/(Rₜₒₜₐₗ) = 24/10 = 2.4 A.
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About Current Electricity
Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.
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