A batch adiabatic reactor at an initial temperature of 373°K is being used for the reaction, A → B. Assume the heat of reaction is - 1kJ/mole at 373°K and heat capacity of both A and B to be constant and equal to 50J/mole.K. The temperature rise after a conversion of 0.5 will be ____________?
Correct answer: B. 10°C
- A. 5°C
- B. 10°C
- C. 20°C
- D. 100°C
Explanation
At 50% conversion, heat released is 0.5 kJ per mole initially present. The adiabatic temperature rise is ΔT = 0.5/0.050 = 10 K, which is also a 10°C rise.
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