A ball whose kinetic energy is "E", is thrown at an angle of 45° with the horizontal. Its kinetic energy at the highest point of its trajectory will be:
Correct answer: B. E/2
- A. E
- B. E/2
- C. E√2
- D. Zero
Explanation
The velocity at the highest point is given by the horizontal component, as the vertical component is zero. Vx = Vcosθ Here V is the initial velocity. The initial kinetic energy is E = 1/2 m V2 K.E = 1/2 mVx2 (as Vx = Vcosθ) = 1/2 m V2 (Cosθ)2 (as E = 1/2 m V2) = E (cos45°)2 = E (1/2) = E/2
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About Work and Energy
Work transfers energy when a force causes displacement, while kinetic energy, gravitational potential energy and power describe motion, position and the rate of energy transfer. The work-energy theorem links net work with change in kinetic energy, and efficiency accounts for energy losses rather than treating them as energy destruction.
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