A ball is thrown vertically upward with the velocity of 98 m/sec, how high does the ball rise?
Correct answer: D. 490 m
- A. 196 m
- B. 2 m
- C. 1/2 m
- D. 490 m
Explanation
The maximum height H reached by a ball thrown vertically upward can be calculated using the formula: H = v2/2g. Here, the initial velocity v = 98 m/s and acceleration due to gravity g = 9.8 m/s2 . Substituting these values: H=982/ 2 x 9.8= 9604/19.6 = 490 m. Therefore, the ball rises to a maximum height of 490 meters.
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About Force and Motion
Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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