A ball falling in a lake of 200 m shows a decrease of 0.1% in its volume. The bulk modulus of elasticity of the material of the ball is: (take g = 10 m/s²)
Correct answer: B. 2 × 10⁹ N/m²
- A. 10⁹ N/m²
- B. 2 × 10⁹ N/m²
- C. 3 × 10⁹ N/m²
- D. 4 × 10⁹ N/m²
Explanation
Bulk modulus is K = -ΔP / (ΔV/V). The pressure change at200 m is ΔP = ρgh = 1000×10×200 = 2 x 10⁶ Pa. The volumestrain ΔV/V is -0.1% or -0.001. Thus, K = (2 x 10⁶) / 0.001 = 2 x10⁹ N/m².
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