A 50Ω resistance wire is stretched such that its length is doubled and its cross section area becomes half. The new resistance is:

Explanation

The resistance R of a wire is given by the formula: R = ρL/A, where ρ is the resistivity, L is the length, and A is the cross-sectional area. When the wire is stretched such that its length doubles and its cross-sectional area is halved, the new length L' is 2L and the new area A' is A/2. The new resistance R' is given by:R' = ρ(2L)/(A/2) = 4ρL/A = 4RTherefore, the new resistance is four times the original resistance, which means R' = 4 * 50Ω = 200Ω.Options A (100Ω) and D (150Ω) are incorrect as they do not correctly account for the quadrupling of resistance. Option C (50Ω) is incorrect because it suggests no change in resistance, which is not possible under these conditions.