Moderate

A 5 kg block is pushed 4 m up a frictionless incline at 30° with a force parallel to the incline. If the work done is 200 J, what is the force applied?

Correct answer: B. 50 N

  • A. 25 N
  • B. 50 N
  • C. 75 N
  • D. 100 N

Explanation

Work = F × d × cosθ. Here, θ = 0° (force parallel to incline), so 200 = F × 4 × 1, F = 200 / 4 = 50 N.

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About Work and Energy

Work transfers energy when a force causes displacement, while kinetic energy, gravitational potential energy and power describe motion, position and the rate of energy transfer. The work-energy theorem links net work with change in kinetic energy, and efficiency accounts for energy losses rather than treating them as energy destruction.

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