A 5 µF capacitor has a potential difference across its plates of 200 volts. The charge on the capacitor is
Correct answer: D. 10-3
- A. 2.5x 1 0-8 C
- B. 10³C
- C. 4 x 10^3C
- D. 10-3
Explanation
The charge Q on a capacitor can be calculated using the formula: Q = C.V Here, Q is the charge on the capacitor, C is the capacitance and V is the potential difference (voltage) across the capacitor. Given that C = 5 µF and V = 200V Q = (5 X 10^-6)X ( 200 )Q = 10 -3 C
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About Electrostatics
Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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