A 5 µF capacitor has a potential difference across its plates of 200 volts. The charge on the capacitor is
Correct answer: D. 10-3
- A. 2.5x 1 0-8 C
- B. 10³C
- C. 4 x 10^3C
- D. 10-3
Explanation
The charge Q on a capacitor can be calculated using the formula: Q = C.V Here, Q is the charge on the capacitor, C is the capacitance and V is the potential difference (voltage) across the capacitor. Given that C = 5 µF and V = 200V Q = (5 X 10^-6)X ( 200 )Q = 10 -3 C
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Electrostatics
Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
Practise Electrostatics
831 free Electrostatics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Electrostatics questions
Which diagram represents the electric fields of a negative point charge, shown by
The large horizontal metal plates are separated by 4 mm. The lower plate is at a potential of -6V.
In EEG, voltage is plotted versus time. This voltage is produced by electrical activity of
The quantity 1/2 εo E2 has the significance of:
Equivalent capacitance is greater than individual capacitances in
If the distance between the plates of parallel plates condenser is increased, its potential will