A 300 mm long conductor is carrying a current of 10 A and is situated at right angles to a magnetic field having a flux density of 0.8 T ; the force on the conductor will be____________?
Correct answer: C. 2.4 N
- A. 240 N
- B. 24 N
- C. 2.4 N
- D. 0.24 N
Explanation
The force on a current-carrying conductor is F = BIL sinθ. With B = 0.8 T, I = 10 A, L = 0.3 m, and θ = 90°, F = 0.8 × 10 × 0.3 = 2.4 N.
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