A 2m tall man standing at the top of 30m tall tower raises a 1 kg mass 0.5 m above his head. The P.E of the raise mass will be (taking head as reference point): (g = 10m/s2)
Correct answer: A. 5 J
- A. 5 J
- B. 320 J
- C. 25 J
- D. All of these
Explanation
Option A is correct.Given that:Height of the man: 2 mHeight of the tower: 30 mMass of the object: 1 kgDistance raised: 0.5 mAcceleration due to gravity: g = 10 m/s²Find out:the potential energy of the object=?The potential energy of an object is given by the following equation:PE = mgh where:m is the mass of the objectg is the acceleration due to gravityh is the height of the object above the reference point In this case, the reference point is the man's head. Therefore, the height of the object is equal to the distance that the object was raised, which is 0.5 m.Substituting the given values, we get:PE = 1 kg * 10 m/s² * 0.5 m = 5 JTherefore, the potential energy of the object is 5 J.
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About Potential Energy
Potential energy is energy stored because of position or configuration, including gravitational potential energy near Earth's surface and elastic energy in a stretched or compressed spring. Questions use changes in potential energy and conservation of mechanical energy, while distinguishing a chosen reference level from an absolute zero of energy.
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