A 2 kg body falls from infinity to the surface of earth. What will be the kinetic energy of the body on reaching the surface of Earth (Assume escape velocity to be 104 ms-1)?
Correct answer: A. 108J
- A. 108J
- B. 1016 J
- C. 1020 J
- D. 1024 J
Explanation
The following is the solution: Kinetic energy = 1/2 mvo2 = 1/2 x 2 (104)2 = 108 J
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