A 18.0 V battery is connected to a capacitor, resulting in 27.0 µC of charge stored on the capacitor. How much energy is stored in the capacitor?
Correct answer: A. 2.43 x 10^-4 J
- A. 2.43 x 10^-4 J
- B. 4.86 x 10^-4 J
- C. 2.43 x 10^-2 J
- D. 4.86 x 10^-2 J
Explanation
E = CV^2/2 = QV/2 = 0.5 X 18 X 2.7x10^-6 = 2.43x10^-4 J As this is a numerical so only one option is correct.
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About Capacitors
Capacitors store electric charge and energy in an electric field between conductors. Work includes capacitance, the relation Q = CV, dielectric materials, charging and discharging, energy formulas, and combinations of capacitors in series and parallel. Electric potential difference is needed to understand why charge and stored energy change.
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