A 100m long conductor carrying current of 2A is at right angle to B of 0.5 wb_m² . The force experienced by the conductor is:
Correct answer: C. 10^7 dynes
- A. 1.2N
- B. 3 dynes
- C. 10^7 dynes
- D. 10^5 dynes
Explanation
This option is correct as 10^7 dynes are equal to 100N. The force can be calculated by: F = BILsinθ In this case, the cylinder is carrying a current of 2A and is placed at right angles to a magnetic field of 0.5 Wb/m². Therefore, the angle between the current and the magnetic field is 90 degrees, and sinθ = 1. Substituting the given values into the formula, we get: F = (0.5 Wb/m²) x (2 A) x (100 m) x sin 90° F = 100 N
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About Magnetic Flux Density
Magnetic flux density measures the magnetic force acting on a current carrying conductor or moving charge in a magnetic field. Work includes the relations B equals F divided by IL and F equals qvB, the tesla as its SI unit, field direction and the distinction between flux density and magnetic flux.
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