A 1-kW radio frequency of 880 KHz. How many quantas per second does it emit?
Correct answer: B. 1.71 x 10^30
- A. 1.71 x 10^21
- B. 1.71 x 10^30
- C. 6.02 x 10^23
- D. 2.85 x 10^26
Explanation
Convert the power to watts:The transmitter's power is given as 1 kW, which is equal to 1000 watts (W). 2. Convert the frequency to hertz:The frequency is given as 880 kHz, which is equal to 880,000 Hz or 880×103 Hz. 3. Calculate the energy of a single photon:The energy of a photon is given by the formula: E=hν, where:E is the energy of the photon. h is Planck's constant, which is approximately 6.626×10−34 J·s. ν is the frequency of the radiation. Therefore:$E = (6.626 \times 10^{-34} \text{ J·s}) \times (880 \times 10^3 \text{ Hz})$E≈5.83088×10−28 J4. Calculate the number of photons emitted per second:The number of photons emitted per second is equal to the total power of the transmitter divided by the energy of a single photon.Number of photons/second = Power / Energy per photon.Number of photons/second = 1000 W/(5.83088×10−28 J)Number of photons/second ≈1.71499×1030Therefore, the radio transmitter emits approximately 1.71×1030 photons per second.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Atomic Structure
Atomic structure covers the discovery of the proton, Planck's quantum theory, hydrogen emission spectra and the evidence for quantized energy levels. You will use quantum numbers to describe orbitals, distinguish s, p, d and f orbital shapes, and write electronic configurations, including the correct order of electron filling.
Practise Atomic Structure
922 free Atomic Structure MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Atomic Structure questions
Total number of electrons in Cu for which the summation of azimuthal quantum number and magnetic quantum number is zero is :
The spin angular momentum for the `s' electron in H-atom is:
If the lowest energy X-rays have λ=3.055×10−8 m, estimate the minimum difference in energy between two Bohr's orbits such that an electronic transition would correspond to the emission of an X-ray. Assuming that the electrons in other shells exert no influence, at what Z(minimum) would a transition from a second energy level to the first, result in the emission of an X-ray?
The angular momentum of an electron in a Bohr's orbit of He+ is 3.1652 x 10^-34 kg.m2 / sec.The wave number of the spectral line emitted when an electron falls from this level to the first excited state is:
Threshold frequency of a metal is fo. When light of frequency v = 2fo is incident on the metal plate, maximum velocity of e- emitted is v1, when frequency of incident radiation is 5fo, maximum velocity of emitted e- is v2. then the ratio of v1/v2 is
Number of waves in the third Bohr's orbit of hydrogen will be: