A 1 kg ball moving in some direction at 8 m/sec hits a 4 kg ball moving at 6 m/sec in the same direction. Assume that the 1 kg ball stops after collision. What will be the velocity, after collision, of the 4 kg ball if the 1 kg ball stops?
Correct answer: C. 8 m/sec
- A. 10 m/sec
- B. 0 m/sec
- C. 8 m/sec
- D. 12 m/sec
Explanation
Conservation of momentum: initial total = 1×8 + 4×6 = 8 + 24 = 32 kg·m/s. If 1 kg stops, all momentum transfers to 4 kg ball: v = 32/4 = 8 m/s.
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