88 gram of carbon dioxide contains
Correct answer: B. 1.204×10²⁴
- A. 6.02×10²³
- B. 1.204×10²⁴
- C. 3.01×10²³
- D. None
Explanation
C= 12g/mol. O= 16g/mol.Mr of CO2= 12 + (16x2) = 44g/molMole=Mass/MrMole= 88/44Mole= 2mol1mole => 6.02x10^23 molecules2mole => x molecules x= 1.204x10^24 molecules
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About Fundamental Concepts of Chemistry
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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