5 calories are equivalent to _ Joule.

1/2 H2(g) ➞ H(g) ∆H = 218 kJ mol-1.In this reaction, ∆H will be called:

1 Kcal is equal to:

2P(s) 3CI2(g) 2PCI3 ∆H= 151.8 kJ PCl3+ CI2(g) , PCI5(g); ∆H = -32.8 kJFrom the following data, the heat of formation of PCI5 comes out to be :

5 mole of an ideal gas expand reversibly from a volume of 8 dm3 to 80 dm3 at a temperature of 27°C. Calculate the change in entropy.

A 100g sample of water at 25 °C and 1 atm. of pressure. Then, 100g of water that has recently heated to 100 °C from 0 °C and then cooled to 25 °C at 1 atm. of pressure.