27g of aluminium reacts with how much O2 to produce aluminium oxide.
Correct answer: D. 1.5 mole
- A. 3 Mole
- B. 0.27 Mole
- C. 0.75 Mole
- D. 1.5 mole
Explanation
2Al+ 3O2- 4 A12O3 Al: Oxyge 54g: 96g I g: 96/54g 27g: 96/54x 27 48g or 1.5 mole
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About Fundamental Concepts of Chemistry
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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