27 g of Al will react with how much mass of O2 to produce Al2O3?
Correct answer: D. 24g of oxygen
- A. 8g of oxygen
- B. 16g of oxygen
- C. 32g of oxygen
- D. 24g of oxygen
Explanation
Option D is the right answerSolution number of moles of Al = given mass/molar mass=27/27= 1 moleThe balance equation for such reaction is4Al + 3O2------- 2Al2O3Al : O24 : 31 : ¾ x1 = 0.750.75 moles of oxygen is used Thus, mass of oxygen = 0.75 x 32 Answer = 24g
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About Moles and Avogadro's Number
The mole connects the microscopic number of particles with measurable mass, using Avogadro's number, 6.022 × 10²³ particles per mole. Questions involve molar mass, conversion between mass, moles and particles, percentage composition, empirical and molecular formulas, and distinguishing atoms, molecules, ions and formula units.
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