18g of water contains _ atoms of hydrogen:
Correct answer: C. 2 x 6.022 x 10^23
- A. 6.022 x 10^23
- B. 3 x 6.022 x 10^23
- C. 2 x 6.022 x 10^23
- D. 4 x 6. 22 x 10^23
Explanation
2 atoms of hydrogen are present in 18 gram of water.So it should be 2 6.022 x 1023To find the number of atoms of hydrogen in 18 grams of water, we need to consider the molecular formula of water, which is H2O. It means there are two hydrogen atoms (H) in one water molecule.The molar mass of water (H2O) is the sum of the molar masses of its constituent atoms:Molar mass of H2O = 2 * molar mass of H + molar mass of OThe molar masses of hydrogen (H) and oxygen (O) are approximately:Molar mass of H ≈ 1 g/molMolar mass of O ≈ 16 g/molMolar mass of H2O ≈ 2 * 1 g/mol + 16 g/mol ≈ 18 g/molNow, we can calculate the number of moles of water (n) in 18 grams:n = mass / molar mass = 18 g / 18 g/mol = 1 molSince there are two hydrogen atoms (H) in one water molecule, there are two moles of hydrogen atoms for every mole of water.Number of atoms of hydrogen = 2 moles of hydrogen * Avogadro's number ≈ 2 * 6.022 x 10^23 ≈ 1.2044 x 10^24 atoms of hydrogenSo, 18 grams of water contains approximately 1.2044 x 1024 atoms of hydrogen.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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