100 ml of each of 0.5 N NaOH, N/5 HCl and N/10 H2SO4 are mixed together. The resulting solution will be:

Explanation

To determine the nature of the resulting solution, calculate the total equivalents of H+ and OH- ions. The 0.5 N NaOH provides 0.05 equivalents of OH- ions in 100 ml. The N/5 HCl provides 0.02 equivalents of H+ ions, and N/10 H2SO4 contributes 0.01 equivalents of H+ ions, totaling 0.03 equivalents of H+ ions. Since 0.05 equivalents of OH- are greater than the 0.03 equivalents of H+, the solution is alkaline. Options A and B are incorrect as they do not account for the excess OH- ions. Option D is incorrect because the solution clearly shows an alkaline nature.