10.0 grams of glucose are dissolved in water to make 100 cm3 of its solution, its molarity is:

Explanation

0.55: This option suggests a molarity of 0.55 for the glucose solution. To determine the molarity, we need to calculate the number of moles of glucose present in the solution. Given that the mass of glucose is 10.0 grams and its molar mass is approximately 180.16 g/mol, we can calculate the number of moles using the formula:Number of moles = Mass of substance / Molar massNumber of moles of glucose = 10.0 g / 180.16 g/mol ≈ 0.0554 molNow, we can calculate the molarity using the formula:Molarity = Number of moles / Volume of solution (in liters)Since the volume of the solution is given as 100 cm3, we need to convert it to liters:Volume of solution = 100 cm3 / 1000 = 0.1 LMolarity = 0.0554 mol / 0.1 L ≈ 0.554 M