1 mole of sucrose (C₁₂H₂₂O₁₁) is equal to:
Correct answer: C. 342 grams of sucrose
- A. 340 grams of sucrose
- B. 344 grams of sucrose
- C. 342 grams of sucrose
- D. 346 grams of sucrose
Explanation
The molar mass of sucrose (C₁₂H₂₂O₁₁) is calculated by summing the atomic masses of all its atoms: (12×12.01) + (22×1.008) + (11×16.00) ≈ 342.3 g/mol. The closest answer is 342 grams.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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