1 gm mole of an alcohol whose molecular weight is 74 contains 48 gms of carbon, 10 gms of hydrogen and 16 gms of oxygen. Its molecular formula is__________________?
Correct answer: A. C4H9OH
- A. C4H9OH
- B. C3H21OH
- C. (C2H4)2H2.OH
- D. C2H33OH
Explanation
The carbon, hydrogen and oxygen amounts correspond to 48/12 = 4, 10/1 = 10 and 16/16 = 1 mole, giving C4H10O. This is conventionally written for the alcohol as C4H9OH.
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