When a body is taken from the equator to the poles, its weight:
Correct answer: B. Increases
- A. Remains same
- B. Increases
- C. Decreases
- D. Increase at N-pole & decreases at S-pole
Explanation
The following is the solution: g′=g−Rω2cos(2λ) g′=g−Rω2cos2λ, where ω is the angular velocity of rotation of Earth about its polar axis, R is the radius of the Earth and λ is the latitude of a place, At poles, λ=90, ∴g p ole=g−Rω2cos(2×90) at equator λ=0, g e quator=g−R(ω)2cos(2×0)=g−R(ω)2 Thus, the acceleration due to gravity decreases from the poles to the equator. Hence, when a body is taken from the poles to the equator on the Earth, its weight decreases.
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