The step of glycolysis that involves the removal of high-energy phosphate by two ADP molecules to get two ATP molecules and two 3PGA molecules is:

Correct answer: B. 7

  • A. 6
  • B. 7
  • C. 9
  • D. 10

Explanation

Step number 7 is the correct step because it is the first ATP-generating reaction in glycolysis. In this step, 1,3-bisphosphoglycerate donates a high-energy phosphate to ADP to form ATP and 3-phosphoglycerate, and since there are two molecules of 1,3-bisphosphoglycerate per glucose, this produces two ATP and two 3-phosphoglycerate molecules. Step 6 is incorrect because it forms 1,3-bisphosphoglycerate from glyceraldehyde-3-phosphate but does not produce ATP. Step 9 is wrong because it only dehydrates 2-phosphoglycerate to phosphoenolpyruvate, preparing the molecule for the next ATP-generating step without producing ATP itself. Step 10 produces ATP as well, but it is the final step of glycolysis and involves phosphoenolpyruvate, not 1,3-bisphosphoglycerate, so it is not the step described in the question.

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